Consider the following equation.
ax2+bx+c=0
Divide both side by ,a, we get,
x2+bxa+ca=0
(x +b2a)2−b24a2+ca=0
(x +b2a)2=b2−4ac4a2
x=−b±√b2−4ac2a
Hence, this is the correct answer.
The roots of a quadratic equation ax2+bx+c=0 are given by −b±√b2−4ac2a, provided b2–4ac≥0.
If b2 – 4ac = 0 then The roots of the Quadratic equation ax2 + bx + c = 0 are given by :