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Question

Prove that root of equation ax2+bx+c=0 isb±b24ac2a

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Solution

Consider the following equation.

ax2+bx+c=0

Divide both side by ,a, we get,

x2+bxa+ca=0

(x +b2a)2b24a2+ca=0

(x +b2a)2=b24ac4a2

x=b±b24ac2a

Hence, this is the correct answer.


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