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Byju's Answer
Standard XII
Mathematics
Sum of Trigonometric Ratios in Terms of Their Product
Prove that: ...
Question
Prove that:
sec
(
π
4
+
θ
)
sec
(
π
4
−
θ
)
=
2
sec
2
θ
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Solution
L
H
S
=
sec
(
π
4
+
θ
)
sec
(
π
4
−
θ
)
=
1
cos
(
π
4
−
θ
)
×
1
cos
(
π
4
+
θ
)
2
2
cos
(
π
4
−
θ
)
cos
(
π
4
+
θ
)
=
2
cos
(
2
π
4
)
+
cos
(
2
θ
)
=
2
cos
(
π
2
)
+
cos
(
2
θ
)
=
2
0
+
cos
(
2
θ
)
=
2
cos
(
2
θ
)
=
2
sec
2
θ
=
R
H
S
Hence L.H.S=R.H.S
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Sum of Trigonometric Ratios in Terms of Their Product
Standard XII Mathematics
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