Prove that- sin 2 24 o -sin 2 6 o - - 5 -1 8

LHS =sin( 24 ^ o + 6 ^ o ) #160; sin( 24 ^ o 6 ^ o ) #160; =sin 30 ^ o sin 18 ^ o = 1 2 [ ( √( 5 ) 1 ) /4 ] ...

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Sum of Trigonometric Ratios in Terms of Their Product

Prove that: ...

Question

Prove that: ${sin}^{2} 24^{o} - {sin}^{2} 6^{o} = \frac{(\sqrt{5} - 1)}{8}$

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{sin}^{2} 42^{o} - {cos}^{2} 78^{o} = \frac{(\sqrt{5} + 1)}{8}

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