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Question

Prove that:

sin2 (π8+A2)sin2(π8A2)=12 sin A

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Solution

LHS,

sin2 (π8+A2)sin2(π8A2)=[sin(π8+A2)+sin(π8A2)][sin(π8+A2)sin (π8A2)][sin π8. cosA2+cos π8. sinA2+sin π8. cos.A2cosπ8. sinA2]=[sinπ8. cosA2+cosπ8. sinA2sinπ8.cosA2 cosπ8.sinA2]=(2sinπ8. cosA2)(2 cos π8. sinA2)=(2 sin π8.cosπ2)(2 sin A8. cos A2)=sin2. π8. sin2. A2=sinπ4. sin A=12 sin A=RHS


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