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Byju's Answer
Standard XII
Mathematics
Trigonometric Ratios for Sum of Two Angles
Prove that si...
Question
Prove that
sin
2
x
+
2
sin
4
x
+
sin
6
x
=
4
cos
2
x
sin
4
x
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Solution
L
.
H
.
S
.
=
sin
2
x
+
2
sin
4
x
+
sin
6
x
=
(
sin
6
x
+
sin
2
x
)
+
2
sin
4
x
sin
A
+
sin
B
=
2
sin
(
A
+
B
2
)
cos
(
A
−
B
2
)
Let
A
=
2
x
,
B
=
6
x
⇒
L
.
H
.
S
=
2
sin
(
2
x
+
6
x
2
)
cos
(
2
x
−
6
x
2
)
+
2
sin
4
x
=
2
sin
(
4
x
)
cos
(
2
x
)
+
2
sin
4
x
=
2
sin
(
4
x
)
(
1
+
cos
(
2
x
)
)
=
2
sin
(
4
x
)
(
2
cos
2
x
)
=
4
cos
2
x
sin
4
x
=
R
.
H
.
S
Hence Proved.
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Q.
sin 2
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