Prove that sin 4- 8 - sin 43- 8 - sin 45- 8 - sin 47- 8 - 3 2

LHS=sin^4π8+sin^43π8+sin^45π8+sin^47π8=14(1 cosπ4)^2+14(1 cos3π4)^2+14(1 cos5π4)^2+14(1 cos7π4)^2 #160; #160; #160; #160; #160; #160; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Product of Trigonometric Ratios in Terms of Their Sum

Prove that s...

Question

Prove that
${sin}^{4} \frac{π}{8} + {sin}^{4} \frac{3 π}{8} + {sin}^{4} \frac{5 π}{8} + {sin}^{4} \frac{7 π}{8} = \frac{3}{2}$

Open in App

Solution

Suggest Corrections

Similar questions

s i n^{4} \frac{π}{8} + s i n^{4} \frac{3 π}{8} + s i n^{4} \frac{5 π}{8} + s i n^{4} \frac{7 π}{8} =

{sin}^{4} \frac{π}{8} + {sin}^{4} \frac{3 π}{8} + {sin}^{4} \frac{5 π}{8} + {sin}^{4} \frac{7 π}{8}

\int_{1}^{4} (c o s x - \frac{3}{x^{5}}) d x

\int_{1}^{4} (c o s (x) - \frac{3}{x^{5}}) d x

{sec}^{4} A (1 - {sin}^{4} A) - 2 {tan}^{2} A = 1.

Join BYJU'S Learning Program