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Byju's Answer
Standard XII
Mathematics
Range of Trigonometric Expressions
Prove that ...
Question
Prove that
sin
(
3
sin
−
1
1
3
)
=
23
27
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Solution
Let
sin
−
1
(
1
3
)
=
x
∴
sin
x
=
1
3
Hence
sin
(
3
x
)
=
sin
(
3
sin
−
1
1
3
)
sin
3
x
=
3
sin
x
−
4
sin
3
x
=
3
×
1
3
−
4
×
1
27
=
1
−
4
27
=
23
27
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0
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Prove:
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√
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√
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Q.
If
9
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×
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×
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−
n
2
)
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Prove that m-n=1
Q.
If
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n
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2
×
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3
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/
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−
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(
27
)
n
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=
1
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−
n
=
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Q.
If
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n
×
3
2
×
(
3
−
n
/
2
)
−
2
−
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27
)
n
3
3
m
×
2
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=
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27
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Q.
If
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b
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⎛
⎜
⎝
3
−
b
2
⎞
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(
27
)
b
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a
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