prove that Sin of a + b + sin of a minus b upon cost of a + b + cos of a minus b is equal to 10

Open in App

Solution

the question must be wrong it is like sin(A+B)+sin(A-B)/cos(A+B)+cos(A-B)=tanA

(sinAcosB+cosAsinB) + (sinAcosB-cosAsinB) / cosAcosB - sinAsinB) + (cosAcosB + sinAsinB)

= sinA/cosA = tanA

Suggest Corrections

Similar questions

Q. if 3sinA+5cosA=5, prove that 3sinA+5cosA=plus or minus 3

if A and B are two odd positive integers such that a is greater than B then prove that one of the two numbers a + b upon Two And A minus b upon 2 is odd and the other is even.

Prove that sin square 20 degree + sin square 70 degree minus 10 square 45 degree is equal to zero

If A={x:x=4 power n minus 3n minus 1 and n belongs to mode of N } and B = {y:y = 9(n -1) and n belongs to mode of N } Prove that A subset of B

If a + b equal to 7 and ab equals to 12 then find the value of a minus b

Join BYJU'S Learning Program

prove that Sin of a + b + sin of a minus b upon cost of a + b + cos of a minus b is equal to 10

the question must be wrong it is like sin(A+B)+sin(A-B)/cos(A+B)+cos(A-B)=tanA (sinAcosB+cosAsinB) + (sinAcosB-cosAsinB) / cosAcosB - sinAsinB) + (cosAcosB + sinAsinB) = sinA/cosA = tanA

the question must be wrong it is like sin(A+B)+sin(A-B)/cos(A+B)+cos(A-B)=tanA

(sinAcosB+cosAsinB) + (sinAcosB-cosAsinB) / cosAcosB - sinAsinB) + (cosAcosB + sinAsinB)

= sinA/cosA = tanA