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Byju's Answer
Standard X
Mathematics
Trigonometric Identities
Prove that s...
Question
Prove that
sin
θ
(
1
+
tan
θ
)
+
c
o
s
θ
(
1
+
cot
θ
)
=
csc
θ
+
sec
θ
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Solution
L
.
H
.
S
.
=
sin
θ
(
1
+
tan
θ
)
+
cos
θ
(
1
+
cot
θ
)
⇒
sin
θ
(
1
+
sin
θ
cos
θ
)
+
cos
θ
(
1
+
cos
θ
sin
θ
)
⇒
sin
θ
+
sin
2
θ
cos
θ
+
cos
θ
+
cos
2
θ
sin
θ
⇒
sin
θ
+
cos
2
θ
sin
θ
+
cos
θ
+
sin
2
θ
cos
θ
⇒
sin
2
θ
+
cos
2
θ
sin
θ
+
cos
2
θ
+
sin
2
θ
cos
θ
⇒
1
sin
θ
+
1
cos
θ
=
cos
e
c
θ
+
sec
θ
=
R
.
H
.
S
H
e
n
c
e
p
r
o
v
e
d
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Similar questions
Q.
Prove that:
sin
θ
(
1
+
tan
θ
)
+
cos
θ
(
1
+
cot
θ
)
=
sec
θ
+
c
o
s
e
c
θ
.
Q.
sin
θ
(
1
+
tan
θ
)
+
cos
θ
(
1
+
cot
θ
)
=
s
e
c
θ
+
c
o
s
e
c
θ
.
Q.
sinθ
(
1
-
cotθ
)
+
cosθ
(
1
-
tanθ
)
=
?
(a) (cos θ + sin θ)
(b) (cos θ − sin θ)
(c) 0
(d) 2 tan θ
Q.
Prave that:
(1)
sin
2
θ
cosθ
+
cosθ
=
secθ
(2)
cos
2
θ
1
+
tan
2
θ
=
1
(3)
1
-
sinθ
1
+
sinθ
=
secθ
-
tanθ
(4)
secθ
-
cosθ
cotθ
+
tanθ
=
tanθ
secθ
(5)
cotθ
+
tanθ
=
cosecθ
secθ
(6)
1
secθ
-
tanθ
=
secθ
+
tanθ
(7)
sec
4
θ
-
cos
4
θ
=
1
-
2
cos
2
θ
(8)
secθ
+
tanθ
=
cos
θ
1
-
sinθ
(9) If
t
anθ
+
1
tanθ
=
2
, then show that
tan
2
θ
+
1
tan
2
θ
=
2
(10)
tanA
1
+
tan
2
A
2
+
cotA
1
+
cot
2
A
2
=
sin
A
cos
A
(11)
sec
4
A
1
-
sin
4
A
-
2
tan
2
A
=
1
(12)
tanθ
secθ
-
1
=
tanθ
+
secθ
+
1
tanθ
+
secθ
-
1
Q.
Prove that:
secθ
+
tanθ
-
1
tanθ
-
secθ
+
1
=
cosθ
1
-
sinθ
Or, Evaluate:
secθ
cosec
(
90
°
-
θ
)
-
tanθ
cot
(
90
°
-
θ
)
+
sin
2
55
°
+
sin
2
35
°
tan
10
°
tan
20
°
tan
60
°
tan
70
°
tan
80
°
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