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Question

Prove that (sin2A cos2B - cos2A sin2B)= (sin2A-sin2B)

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Solution

1) L.H.S.

sin2Acos2B -cos2Asin2 B

SIN2A(1-sin2B)-(1-sin2A)sin2B
sin2A -sin2Asin2B -sin2B +sin2Asin2B
sin2A -sin2B
R.H.S. PROVED

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