MyQuestionIcon

1073

You visited us 1073 times! Enjoying our articles? Unlock Full Access!

Trigonometric Ratios of Multiples of an Angle

Prove that Si...

Question

Prove that Sin3x+sin2x-sinx=4sinx * cos(x/2)cos(3x/2)

Open in App

Solution

Suggest Corrections

thumbs-up

1

Similar questions

Q. Prove that :

\frac{sin x - sin 3 x}{{sin}^{2} x - {cos}^{2} x} = 2 sin x

\frac{{cos}^{3} x - {sin}^{3} x}{cos x - sin x} = \frac{1}{2} (2 + sin 2 x)

sin 3 x + sin 2 x - sin x = 4 sin x cos \frac{x}{2}, cos \frac{3 x}{2}

Q. Solve the following equations:
(i)

\cos x + \cos 2 x + \cos 3 x = 0

\cos x + \cos 3 x - \cos 2 x = 0

\sin x + \sin 5 x = \sin 3 x

\cos x \cos 2 x \cos 3 x = \frac{1}{4}

\cos x + \sin x = \cos 2 x + \sin 2 x

\sin x + \sin 2 x + \sin 3 = 0

\sin x + \sin 2 x + \sin 3 x + \sin 4 x = 0

\sin 3 x - \sin x = 4 \cos^{2} x - 2

\sin 2 x - \sin 4 x + \sin 6 x = 0

\frac{sin x - sin 3 x}{{sin}^{2} x - {cos}^{2} x} = 2 sin x

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Multiple and Sub Multiple Angles

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Trigonometric Ratios of Multiples of an Angle

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon