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Question

Prove that 1cosA1+cosA+1+cosA1cosA=2cosecA

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Solution

LHS=1cosA1+cosA+1+cosA1cosA

Rationalize the denominators by multiplying suitable factors

=1cosA1+cosA×1cosA1cosA+1+cosA1cosA×1+cosA1+cosA

=1cosAsinA+1+cosAsinA

=2sinA

=2cosecA

Hence proved

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