Prove that i-1-cos 2 - 1-cos 2 -tan-

√(1 cos 2 θ/1 + cos 2θ)= √(2 sin^2 θ/2 cos^2 θ) = sin θ/cos θ = tan θ = RHS ...

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Sin2A and Cos2A in Terms of tanA

Prove that i/...

Question

Prove that :

$\sqrt{\frac{1 - c o s 2 θ}{1 + c o s 2 θ}} = t a n θ$

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\sqrt{\frac{1 - cos 2 θ}{1 + cos 2 θ}} = tan θ

\frac{1 - c o s 2 θ + s i n 2 θ}{1 + c o s 2 θ + s i n 2 θ} = t a n θ

{tan}^{2} θ {cos}^{2} θ = 1 - {cos}^{2} θ

sin θ + {sin}^{2} θ = 1

{cos}^{2} θ + {cos}^{4} θ = 1

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