Prove that - asin B - sin C - 0

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Principal Solution of Trigonometric Equation

Prove that ...

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Prove that $\sum a (sin B - sin C) = 0$

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\sum a (sin B - sin C) = 0

$a (s i n B - s i n C) + b (s i n C - s i n A) + c (s i n A - s i n B) = 0$

a sin (B - C) + b sin (C - A) + c sin (A - B) = 0

\frac{sin (A - B)}{sin A sin B} + \frac{sin (B - C)}{sin B sin C} + \frac{sin (C - A)}{sin C sin A} = 0

△ A B C, \sum a (sin B - sin C) =

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