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Byju's Answer
Standard X
Mathematics
Range of Trigonometric Ratios from 0 to 90 Degrees
Prove that : ...
Question
Prove that :
t
a
n
2
θ
−
1
c
o
s
2
θ
=
−
1
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Solution
We have,
L.H.S. =
t
a
n
2
θ
−
1
c
o
s
2
θ
⇒
L.H.S. =
t
a
n
2
θ
−
s
e
c
2
θ
..........................
[
∵
1
c
o
s
θ
=
s
e
c
θ
∴
1
c
o
s
2
θ
=
s
e
c
2
θ
]
⇒
L.H.S. =
−
(
s
e
c
2
θ
−
t
a
n
2
θ
)
=
−
1
=
R
.
H
.
S
.
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0
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Standard X Mathematics
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