Prove that- tan A -2tan 2A -4tan 4A -8 8A - A

Transfer tanA to RHS ∴ 2tan 2A +4tan 4A +8 8A = A tan A =2 2A ∴ 4tan 4A +8 8A =2( 2A tan 2A #160; ) =2.2 4A ∴ 8 8A =4[ 4A ...

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Trigonometric Equations

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Prove that: $tan A + 2 tan 2 A + 4 tan 4 A + 8 cot 8 A = cot A$

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tan A + 2 tan 2 A + 4 tan 4 A + 8 cot 8 A = k cot A

k

Find the value of tan A + 2 tan2A + 4 tan4A + 8 cot 8A

$\frac{s e c A - t a n A}{s e c A + t a n A} = 1 - 2 s e c A t a n A + 2 t a n^{2} A$

\frac{sec A - tan A}{sec A + tan A} = 1 - 2 sec A tan A + 2 {tan}^{2} A

\frac{s e c A - t a n A}{s e c A + t a n A} = 1 - 2 s e c A t a n A + 2 t a n^{2} A

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