Prove that tan 3-4 - -tan -4 - - - - 1

Consider the L.H.S. #10; #10; =tan( 3π4+θ #160; )tan( π #10;4+θ #160; ) #10; #10;We know that, #10; #10; tan( A+B )=tanA+tanB1 tan ...

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Cos(A+B)Cos(A-B)

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Prove that $tan (\frac{3 π}{4} + θ) tan (\frac{π}{4} + θ) = - 1$

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