Prove that tan-sin-cos-tan 2 - 2 -

Here we have to prove that First we take LHS and use the identities Now we take RHS nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; ...

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Value of Standard Angle(30,60,90)

Prove that ta...

Question

Prove that $\frac{\tan θ - \cot θ}{\sin θ \cos θ} = \tan^{2} θ - \cot^{2} θ$ .

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\frac{1 + {tan}^{2} θ}{1 - {cot}^{2} θ} = {(\frac{1 - tan θ}{1 - cot θ})}^{2}

Prove the following trigonometric identities:

$\frac{1 + t a n^{2} θ}{1 + c o t^{2} θ} = {(\frac{1 - t a n θ}{1 - c o t θ})}^{2} = t a n^{2} θ$

\frac{sin θ - cos θ + 1}{sin θ + cos θ - 1} = \frac{1}{sec θ - tan θ}

{sec}^{2} θ = 1 + {tan}^{2} θ

{sec}^{2} θ - cos e c^{2} θ = {tan}^{2} θ - {cot}^{2} θ

{sec}^{2} θ = 1 + {tan}^{2} θ

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