Prove that the area of the triangle is 1 2 a 2 sin B sin C sin A

Area= 1 2 absin C = 1 2 a ^ 2 . b a sin C = 1 2 a ^ 2 sin B sin C #160; sin A #160; ...

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Quadratic Formula

Prove that th...

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Prove that the area of the triangle is $\frac{1}{2} a^{2} \frac{sin B sin C}{sin A}$

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Δ A B C, \frac{1}{2} a^{2} \frac{s i n B s i n C}{s i n A} =

Δ A B C, \frac{a^{2} + b^{2}}{a^{2} - b^{2}} = \frac{sin (A + B)}{sin (A - B)}

sin \frac{A}{2} sin \frac{B}{2} sin \frac{C}{2} \leq \frac{1}{8}

Δ A B C

sin A + sin B > sin C

\sqrt{\frac{sin A + 1}{1 - sin A}} + \sqrt{\frac{1 - sin A}{sin A + 1}} = 2 sec A

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