CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

Prove that the coefficient of xn in the expansion 11+x+x2 is 1,0,1 according as n is of the form 3m,3m1 or 3m+1

Open in App
Solution

let
y=11+x+x2

multiply and divide by 1-x

y=1x1x3=(1x)[1x3]1

expanding the later bracket

=(1x)[1+x3+2.x62!+2.3x93!.......(1)(2).(3)..(m)(x)3mm!.............]


=(1x)[1+x3+x6+x9......x3m3+x3m.............]

coefficient of x3m
=1

coefficient of x3m+1
=1

coefficient of x3m1
=0 because no such term exits


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Visualising the Terms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon