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Question

Prove that the coefficient of xr in the expansion of (14x)12 in |2r|(|r|)2

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Solution

(1+x)n=1+nx+(n)(n1)x22!+......(n!)xnn!

Where n is negative or fraction

given that

(14x)12=1+(12)x+(12)(121)x22!+......(12)(121)...(12r+1)xrr!


coefficient of xr is

(1).(3).(5)....(12r)2r.r!


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