Prove that the cubic equation whose roots are twice to each of the roots x^3 + 2x^2 -4x + 1 = 0 is x^3 + 4x^2 - 16x + 8 =0

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x^{3} + 2 x^{2} - 4 x + 1 = 0

x^{3} - 2 x^{2} - 2 x + 3 = 0

x^{3} - 8 x^{2} + 16 x - 9 = 0

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What is the product of roots of the cubic equation $x^{3}$ -9 $x^{2}$ +16x-30=0 __

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