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Question

Prove that the equation x+1y+y+1x=4has infinitely many solutions in positive integers.

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Solution

Suppose that the equation has a solution (x1,y1) with x1y1
Clearing denominators, we can write the equation under the form x2(4y1)x+y2+y=0
that is, a quadratic in x. One of the roots is x1, therefore. by Vieta's theorem, the second one is 4y11x1.
Observe that 4y11x14x11x1=3x112x1>0
Hence, 4y11x1 is a positive integer. It follows that (4y11x1,y1)
is another solution of the system, Because the equation is symmetric, we obtain that (x2+y2)=(y1,4y11x1)
is also a solution.To end the proof, observe that x2+y2=5y11x1+y1
and that (1,1) is a solution. Thus , we can generate infinitely many solutions: (1,1)(1,2)(2,6)

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