It is given that
In Δ ABC
D, E and F are the mid-points of AB, BC and CA
Now join DE, EF and FD
To find:
Δ ADF ≅ Δ DBE ≅ Δ ECF ≅ Δ DEF
To prove:
In Δ ABC
D and E are the mid-points of AB and BC
DE || AC or FC
Similarly DF || EC
DECF is a parallelogram (1 Mark)
We know that
Diagonal FE divides the parallelogram DECF in two congruent triangles DEF and CEF
Δ DEF ≅ Δ ECF …… (1) (1 Mark)
Here we can prove that
Δ DBE ≅ Δ DEF …. (2)
Δ DEF ≅ Δ ADF ……. (3)
Using equation (1), (2) and (3)
Δ ADF ≅ Δ DBE ≅ Δ ECF ≅ Δ DEF (2 Mark)