wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Prove that the function f given by f(x) = x2x + 1 is neither strictly increasing nor strictly decreasing on (−1, 1).

Open in App
Solution

The given function is f(x) = x2x + 1.

The pointdivides the interval (−1, 1) into two disjoint intervals i.e.,

Now, in interval

Therefore, f is strictly decreasing in interval.

However, in interval

Therefore, f is strictly increasing in interval.

Hence, f is neither strictly increasing nor decreasing in interval (−1, 1).


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Change of Variables
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon