Prove that the function f(x) = log (2x-1) notderivable at x=0.

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f (x) = \frac{x - 1}{x + 1}

f (2 x) = \frac{3 f (x) + 1}{f (x) + 3}

f (x) = 2 x^{2} + 3 x - 5

x = - 1

f^{'} (0) + 3 f^{'} (- 1) = 0

{\int_{0}}^{1} {sin}^{- 1} (\frac{2 x}{1 + x^{2}}) d x = \frac{π}{2} - log 2

x = 0

f (x) = \frac{sin 3 x}{tan 2 x}, x < 0

= \frac{log (1 + 3 x)}{e^{2 x} - 1}, x > 0

= \frac{3}{2}, x = 0

\int_{0}^{\frac{π}{2}} (2 log sin x - log sin 2 x) d x

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