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Byju's Answer
Standard XII
Mathematics
Derivative of Standard Functions
Prove that th...
Question
Prove that the greatest integer function defined by
f
(
x
)
=
[
x
]
,
0
<
x
<
3
is not differentiable at
x
=
1
and
x
=
2
.
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Solution
f
(
x
)
=
[
x
]
is discontinuous at all integral points.
As
x
∈
(
0
,
3
)
, the integers in this interval are
x
=
1
and
x
=
2
.
Hence, at these points the function is discontinuous.
As, the function is discontinuous, it is non differentiable.
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Similar questions
Q.
Prove that greatest integer function defined by
f
(
x
)
=
[
x
]
,
0
<
x
<
3
is not differentiable at
x
=
1
Q.
Prove that the greatest integer function defined by is not differentiable at x = 1 and x = 2.
Q.
Examine for continuity and differentiability at the points
x
=
1
,
x
=
2
, the function
f
defined by
f
(
x
)
=
{
x
[
x
]
,
0
≤
x
<
2
(
x
−
1
)
[
x
]
,
2
≤
x
≤
3
where
[
x
]
=
greatest integer less than or equal to
x
Q.
Show that the function
f
defined by
f
(
x
)
=
⎧
⎪
⎨
⎪
⎩
2
x
+
3
if
−
3
≤
x
<
−
2
x
+
1
if
−
2
≤
x
<
0
−
x
+
2
if
0
≤
x
≤
1
is not differentiable at
x
=
−
2
and
x
=
0.
Q.
Prove that the function
f
(
x
)
=
[
x
]
is not continuous at
x
=
0
. Where
[
x
]
is the greatest integer function.
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