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Question
Prove that the Greatest Integer
Function f: R → R given by f(x)
= [x], is neither one-once nor onto, where [x] denotes
the greatest integer less than or equal to x.
Prove that the Greatest Integer Function f: R → R given by f(x) = [x], is neither one-once nor onto, where [x] denotes the greatest integer less than or equal to x.
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Solution
f:
R → R is given by,
f(x)
= [x]
It is seen
that f(1.2) = [1.2] = 1, f(1.9) = [1.9] = 1.
∴
f(1.2) = f(1.9), but 1.2 ≠
1.9.
∴ f
is not one-one.
Now,
consider 0.7 ∈ R.
It is
known that f(x) = [x] is always an integer.
Thus, there does not exist any element x ∈
R such that f(x) = 0.7.
∴ f
is not onto.
Hence, the
greatest integer function is neither one-one nor onto.
f: R → R is given by,
f(x) = [x]
It is seen that f(1.2) = [1.2] = 1, f(1.9) = [1.9] = 1.
∴ f(1.2) = f(1.9), but 1.2 ≠ 1.9.
∴ f is not one-one.
Now, consider 0.7 ∈ R.
It is known that f(x) = [x] is always an integer. Thus, there does not exist any element x ∈ R such that f(x) = 0.7.
∴ f is not onto.
Hence, the greatest integer function is neither one-one nor onto.
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