Question

Prove that the kinetic energy of a freely falling object on reaching the ground is nothing but the transformation of its initial potential energy.

Answer 1

Top
P.E$=$mgh
K.E.$=0$
Bottom
P.E$=0$
K.E.$=\frac{1}{2}$mv${}^2$
According to the law of conversation of energy
Energy${}_{top}=$Energy${}_{bottom}$

$\therefore$P.E.${}_{top}=$K.E${}_{bottom}$