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Question

Prove that the length of the chord joining the points of contact of tangents drawn from the point (x1,y1) is y21+4a2y214ax1a.

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Solution

Tangents are drawn from A(x1,y1) and let the point of contact be P(at21,2at1),Q(at22,2at2)

PQ=(at22at21)2+(2at22at1)2PQ=a(t2t1)2(t2+t1)2+4(t2t1)2PQ=a(t2t1)(t2+t1)2+4...........(i)

Equation of chord of contact w.r.t. A is T=0

yy1=2a(x+x1)2axyy1+2ax1=0......(ii)

Equation of chord joining AB is

(t1+t2)y=2x+2at1t22x(t1+t2)y+2at1t2=0......(iii)

Comparing (ii) and (iii)

22a=(t1+t2)y1=2at1t22ax11a=t1+t2y1=t1t2x1t1+t2=y1a,t1t2=x1a(t1+t2)2=y21a2...........(iv)(t1t2)2=(t1+t2)24t1t2(t1t2)2=y21a24x1a=y214ax1a2t1t2=y214ax1a.........(v)

substituting (iv) and (v) in (i)

PQ=ay214ax1ay21a2+4PQ=ay214ax1ay21+4a2aPQ=y214ax1y21+4a2a


697810_641453_ans_f92795bdaa2b4952b06aff7f0aceaa4c.png

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