Let a circle with centre O and external point P.
Two tangents PQ and PR are drawn.
To prove : PQ=PR
Construction: Join radius OQ and OR also join O to P.
Proof : In △OQP and △ORP
OQ=OR (Radii)
∠ Q=∠R [Each 90∘,radius⊥tangents) ]
OP=OP (Common side)
∴△OQP ≅△ORP (RHS Congruence rule.)
By CPCT PQ=PR
Hence, proved.