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Question

Prove that the line segment joining the points of contact of two parallel tangents of a circle, passes through its centre.

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Solution



Consider AB and CD are two parallel tangents to the circle.

Consider P and Q be the point of contact and POQ be a line segment.

Construction: Join OP and OQ where O is the centre of a circle.

Proof: OQ ⊥CD and OP ⊥ AB.

Since AB || CD, OP || OQ.

As OP and OQ pass through O,

Hence, POQ is a straight line which passes through the centre of a circle.


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