Let,
PQ and
RS be two parallel tangents to a circle with cantre
O where
M,N be the points of contact of the two tangents
PQ,RS to the circle respectively.
We have to prove that the line MN passes through the centre O of the circle.
Here, OM and OA are joined.
OA∥PQPM∥AO∴∠PMO+∠AOM=180o[sumoftwoadjacentinteriorangles]
but, ∠PMO=90o[∵Atangenttoacircleisperpendiculartotheradiusthroughpointofcontact]
So, 90o+∠AOM=180o⇒∠AOM=90o∴∠AON=90o∠AOM+∠AON=180o
∴ MN is a straight line and it passes through O which is the centre of the given circle.
Hence, proved.