Let the points are A(1,5),B(2,3) and C(−2,−11) respectively i.e. co-ordinate of A is (1,5), co-ordinate of B is ( 2, 3) and co-ordinate of C is (-2, -11).
AB=√(2−1)2+(3−5)2=√12+(−2)2=√1+4=√5BC=√(−2−2)2+(−11−3)2=√16+196=√212CA=√(1−(−2))2+(5−(−11))2=√9+256=√265
It is clear that sum of distances of any two sides is not equal to third side. So these points are not collinear.