Question

Prove that the points (3, 0), (6, 4) and (-1, 3) are verticies of a right-angled isoceles triangle.

Solution

Let A (3,0) B (6,4) and C (-1,3) now use distance formula , AB=√(6−3)2+(4−0)2=√(25)=5 BC=√(−1−6)2+(3−4)2=√(50) CA=√((3+1)2+(−3)2=5. you see , BC2=AC2+AB2 which is related to Pythagoras theorem . hence , ABC is the vertices of right angle isoceles triangle .in which A is right angle .

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