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Question

Prove that the points (3, 0), (6, 4) and (-1, 3) are verticies of a right-angled isoceles triangle.


Solution

Let A (3,0) B (6,4) and C (-1,3)
now use distance formula ,
AB=(63)2+(40)2=(25)=5
BC=(16)2+(34)2=(50)
CA=((3+1)2+(3)2=5.

you see ,
BC2=AC2+AB2
which is related to Pythagoras theorem .
hence , ABC is the vertices of right angle isoceles triangle .in which A is right angle .

 

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