wiz-icon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

Prove that the straight line y = mx + c touches the parabola y2=4a(x+a) if c=ma+am.

Open in App
Solution

satisfy the given line with parabola
and then put D=b24ac=0 quad eqn.ax2+bx+c
parabola
y2=4a(x+a) line y=mx+c
(mx+c)2=4a(x+a)
(mx)2+2mxc+c2=4a(x+a)
(mx)2+2mxc+c24ax4a2=0
Now put D = 0
D=b24ac=0
(2mc4a)24m2(c24a2)=0
a2mca+m2a2=0
a2+m2a2=mca
c=am+ma

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon