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Question

Prove that the tangents drawn at the end points of a chord of a Circle make equal angles with the chord.

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Solution

REF.Image.
Let AB be a chord of a circle with center O and
let AR and BR
be the tangents
at A and B
Let the tangent meet at R. Join OR
and suppose OR meets AB at C.
To Prove : RAC=RBC
Proof : In RAC and RBC
tangents from an external point
to a circle are equal
RA=RB
RA and RB are equally inclined to OR
ARC=BRC
RC=RC (common in both triangles)
RACRBC according to
SAS congruence
Hence proofes
RAC=RBC

1179806_627725_ans_b537d4e2c07a4b878618dcd87336b520.jpeg

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