Let AB be a diameter of the circle. Two tangents PQ and RS are drawn at points A and B respectively.
Radii of the circle to the tangents will be perpendicular to it.
∴OB⊥RS and,
∴OA⊥PQ∠OBR=∠OBS=∠OAP=∠OAQ=90∘
From the figure,
∠OBR=∠OAQ (Alternate interior angles)
∠OBS=∠OAP (Alternate interior angles)
Since alternate interior angles are equal, lines PQ and RS will be parallel.
Hence, the tangents drawn at the ends of a diameter of a circle are parallel.