Question

Prove that the virtual image produced by a convex mirror is always diminished in size and is located between the focus and the pole.

Answer 1

Given mirror is convex mirror

From the mirror formula

$\frac{1}{v}$ = $\frac{1}{f}$ – $\frac{1}{u}$ .

Since f > 0 (convex mirror) and u < 0,

On the basis of the above information we can conclude that

$\frac{1}{v}$ > $\frac{1}{f}$ i.e. v < f

Since v < f it means that image distance is less than focal length so the image is located between the pole and the focus)

And from above v < |u|

So the image is smaller than the object.