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Question

Prove that the virtual image produced by a convex mirror is always diminished in size and is located between the focus and the pole.

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Solution

Given mirror is convex mirror

From the mirror formula

1v = 1f1u .

Since f > 0 (convex mirror) and u < 0,

On the basis of the above information we can conclude that

1v > 1f i.e. v < f

Since v < f it means that image distance is less than focal length so the image is located between the pole and the focus)

And from above v < |u|

So the image is smaller than the object.


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