[ In Δ ABC and Δ EDC; ⇒∠ ABC= 90^ 0 ( given ) #160;; ⇒∠ EDC= 90^ 0 ( given ) #1 ...

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Prove that ...

Question

Prove that $△ A B C \sim △ E D C$

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Solution

$\begin{matrix} I n Δ A B C a n d Δ E D C \Rightarrow ∠ A B C = 90^{0} (g i v e n) \Rightarrow ∠ E D C = 90^{0} (g i v e n) ∴ B C = C D a n d A B = E D (a l t i t u d e s) t h e n, Δ A B C \sim Δ E D C B y S . A . S c r i t e r i a \end{matrix}$

Hence, proved.

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