Prove that $△$ AOD $≅$ $△$ BOC. [2 Marks]

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Solution

In $△$ AOD and $△$ BOC, we have,

OA = OB (given)

OD = OC (given)

$∠$ AOD = $∠$ BOC (vertically opposite angles)

Therefore, $△$ AOD $≅$ $△$ BOC (by SAS congruence condition) [1 Mark]

Since $∠$ AOD and $∠$ BOC are the included angles for sides OA & OD and OB & OC respectively, we have the triangles congruent by using SAS congruence rule.
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Prove that △AOD ≅ △BOC. [2 Marks]

Prove that $△$ AOD $≅$ $△$ BOC. [2 Marks]