prove that value of R is 8.314

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The value of $Δ H - Δ U$ for the following reaction at $27^{\circ}$ will be : $2 N H_{3 (g)} \to N_{2 (g)} + 3 H_{2 (g)}$

R

8.314 X

X

l o g_{10}

A ⇌ B

△_{r} H_{298 K} = - 54.07 k J m o l^{- 1}, △_{r} S_{298 K}^{o} = 10 J K^{- 1} m o l^{- 1} a n d R = 8.314 J K^{- 1} m o l^{- 1}; 2.303 \times 8.314 \times 298 = 5705) .

The value of $l o g_{10} K$ for a reaction $A ⇌ B$ is

(Given: $Δ_{r} H_{298 k}^{0} = - 54.07 k J^{- 1} m o l^{- 1}; 2.303 \times 8.314 \times 298 = 5705)$

sin x + cos x

\sqrt{2}

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