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Question

Prove that x − 1 is a factor of xn − 1 for every natural number n.

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Solution

Factor theorem says that for the polynomial p(x) and for the number a, if we have p(a) = 0, then (x − a) is a factor of p(x).

Given: Polynomial xn 1

Divisor = (x 1)

Putting x = 1 in the given polynomial:

(1)n 1

= 1 1 { (1)n = 1, for all natural numbers n}

= 0

( x 1) is a factor of the polynomial xn 1 for every natural number n.


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