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Byju's Answer
Standard IX
Mathematics
Algebraic Identities
Prove that: ...
Question
Prove that:
x
3
−
y
3
=
(
x
−
y
)
(
x
−
y
ω
)
(
x
−
y
ω
2
)
.
ω
being cube root of unity.
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Solution
Now,
x
3
−
y
3
=
(
x
−
y
)
(
x
2
+
x
y
+
y
2
)
=
(
x
−
y
)
{
x
2
−
(
ω
+
ω
2
)
x
y
+
y
2
ω
3
}
[ Since
ω
3
=
1
and
1
+
ω
+
ω
2
=
0
]
=
(
x
−
y
)
(
x
−
y
ω
)
(
x
−
y
ω
2
)
.
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Similar questions
Q.
(
x
+
y
+
z
)
(
x
+
y
ω
+
z
ω
2
)
(
x
+
y
ω
2
+
z
ω
)
=
E
, where
ω
is the cube root of unity. Then the value of
E
is
Q.
If
1
,
ω
,
ω
2
are the cube roots of unity, then
(
x
+
y
+
z
)
(
x
+
y
ω
+
z
ω
2
)
(
x
+
y
ω
2
+
z
ω
)
equal to
Q.
Let
ω
being cube root of unity, then if
x
=
a
+
b
,
y
=
a
ω
+
b
ω
2
,
a
ω
2
+
b
ω
. Then show that
x
2
+
y
2
+
z
2
=
6
a
b
and
x
3
+
y
3
+
z
3
=
3
(
a
3
+
b
3
)
.
Q.
Prove that :
x
2
+
x
y
+
y
2
=
(
x
−
y
ω
)
(
x
−
y
ω
2
)
Q.
If
ω
is cube root of unity the linear factors of
x
3
+
y
3
in complex number is
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