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Question

Prove that x & y are not odd multiple of π2 then tanx=tanyx=nπ+y, where nz

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Solution

If x and y are not odd multiple at π2 then,
tanxtanyx=nπ+ynz
Proof:-
Given that
tanx=tany
sinxcosx=sinycosysinxcosy=cosxsinysinxcosycosxsiny=0sin(xy)=0[sinθ=0θ=nπ]xy=nπx=nπ+y
Where,
n±1,±2.


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