Prove that xy - log y - c is the solution of dydx - y21-xy xy - 1

xy=log y+c xdydx+y=1ydydx+0 dydx ( 1y x )=y dydx ( 1 xyy )=y dydx=y^21 xy Hence proved. ...

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General Solution of a Differential Equation

Prove that ...

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Prove that $x y = l o g$ $y + c$ is the solution of $\frac{d y}{d x} = \frac{y^{2}}{1 - x y} (x y \neq 1)$

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x y = log y + c

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