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Question

Prove the following :
secθ+secϕ+(tanθtanϕ)secθ+secϕ(tanθtanϕ)=tan(π4+θ2)tan(π4+ϕ2)

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Solution

L.H.S=(cosθ+cosϕ)+sin(θϕ)(cosθ+cosϕ)sin(θϕ)
=cosθ+ϕ2+sinθϕ2cosθ+ϕ2sinθϕ2 ....(1)
we have cancelled the common factor 2 cos θϕ2
Now replace cos θ+ϕ2 by sin [π2(θπ2)] and apply sin C ± sin D etc

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