Prove the following- sin x-sin 3x-sin2 x-cos2 x - 2 sin x

LHS =sin x sin 3x /sin^ 2 x cos^ 2 x = 2cos( x+3x 2 #160;) #160;sin( x 3x 2 #160;) #160; #160;/ cos 2x #160; =2sinx #160; ...

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Principal Solution of Trigonometric Equation

Prove the fol...

Question

Prove the following:
$\frac{sin x - sin 3 x}{{sin}^{2} x - {cos}^{2} x} = 2 sin x$

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\frac{sin x - sin 3 x}{{sin}^{2} x - {cos}^{2} x} = 2 sin x

Prove the following:
$\frac{sin x - sin 3x}{{sin}^{2} x - {cos}^{2} x} = 2 sin$ x.

\cos x + \cos 2 x + \cos 3 x = 0

\cos x + \cos 3 x - \cos 2 x = 0

\sin x + \sin 5 x = \sin 3 x

\cos x \cos 2 x \cos 3 x = \frac{1}{4}

\cos x + \sin x = \cos 2 x + \sin 2 x

\sin x + \sin 2 x + \sin 3 = 0

\sin x + \sin 2 x + \sin 3 x + \sin 4 x = 0

\sin 3 x - \sin x = 4 \cos^{2} x - 2

\sin 2 x - \sin 4 x + \sin 6 x = 0

sin x + sin 2 x + sin 3 x = cos x + cos 2 x + cos 3 x .

\frac{c o s 4 x + c o s 3 x + c o s 2 x}{s i n 4 x + s i n 3 x + s i n 2 x} = c o t 3 x

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