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Question

Prove the following equations.
(i) log101600=2+4log102
(ii) log1012500=2+3log105
(iii) log102500=42log102
(iv) log50.00125=35log510

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Solution

(i) log101600=log10100+log1016=2+log1024=2+4log102

(ii) log1012500=log10100+log1053=2+3log105

(iii) log102500=log10100004=4log104=42log102

(iv) log50.00125=log5(125105)=log553log5105=35log510


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